In a gas mixture of He, Ne, and Ar with a total pressure of 8.40 atm, the mole fraction of Ar is __________ if the partial pressures of He and Ne are 1.50 and 2.00 atm, respectively.

Respuesta :

Answer: 1.71

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

[tex]p_{total}=p_A+p_B+p_C[/tex]

Given :

[tex]p_{total}[/tex] = total pressure of gases = 8.40 atm

[tex]p_{He}[/tex] = partial pressure of helium = 1.50 atm

[tex]p_{Ne}[/tex] = partial pressure of neon = 2.00 atm

[tex]p_{Ar}[/tex] = partial pressure of argon = ?

putting in the values we get:

[tex]8.40=1.50+2.00+p_{Ar}[/tex]

[tex]p_{Ar}=4.90[/tex]

To calculate the vapor pressure of the solution, we use the law given by Dalton, which is:

[tex]P_{total}=(p_{Ar}\times \chi_{Ar})[/tex]

We are given:

[tex]p_Ar[/tex] = partial pressure of argon = 4.90

[tex]\chi_{Ar}[/tex] = mole fraction of argon = ?

Putting values in above equation, we get:

[tex]8.40=[(4.90\times \chi_{Ar})[/tex]

[tex]\chi_{Ar}=1.71[/tex]

Thus the mole fraction of Ar is 1.71