Respuesta :
Answer:
0.0041 Nm
Explanation:
Parameters given:
Current, I = 1.85 A
Length of side of the square, L = 9.26 cm = 0.0926 m
Magnetic field, B = 0.259 T
The magnetic torque on the loop is given as:
τ = N * I * A * B
Where N = number of turns = 1
I = current
A = area of the loop = L * L = 0.0926²
B = magnetic field
We're told that current is acting on a perpendicular axis to the magnetic field.
Therefore:
τ = 1 * 1.85 * 0.0926² * 0.259
τ = 0.0041 Nm
The magnetic torque is 0.0041 Nm.
Answer:
There is no torque (τ = 0)
Explanation:
The torque is acting on a current carrying loop. When it is placed in a magnetic field B, the expression is the follow:
τ = I*A*B*cosθ
Due the field B acting along the +z direction, and xy-plane, it is perpendicular at coil. Thus, θ = 90°, cos90 = 0, then:
τ = 0, there is no torque with this condition
