Answer:
a) On Earth
490N
b) On the Moon
85N
c) On Mars
185N
d)in outer space traveling with constant velocity.
0
Explanation:
The weight is defined as:
[tex]W = mg[/tex] (1)
Where m is the mass and g is the gravity
a) On Earth [tex]g = 9.8m/s^{2}[/tex]
Then, equation 1 can be used:
[tex]W = (50Kg)(9.8m/s^{2})[/tex]
[tex]W = 490Kg.m/s^{2}[/tex]
but 1N = Kg.m/s^{2}
[tex]W = 490N[/tex]
Hence, the weight of the astronaut on Earth is [tex]490N[/tex]
b) On the Moon [tex]g = 1.7m/s^{2}[/tex]
[tex]W = (50Kg)(1.7m/s^{2})[/tex]
[tex]W = 85N[/tex]
Hence, the weight of the astronaut on the Moon is [tex]85N[/tex]
c) On Mars [tex]g = 3.7m/s^{2}[/tex]
[tex]W = (50Kg)(3.7m/s^{2})[/tex]
[tex]W = 185N[/tex]
Hence, the weight of the astronaut on Mars is [tex]185N[/tex]
(d) in outer space traveling with constant velocity.
Tanking into consideration that the astronaut is traveling in outer space at a constant velocity, it can be concluded that the acceleration will be zero.
Remember that the acceleration is defined as:
[tex]a = \frac{v_{f} - v_{i}}{t}[/tex]
Since the acceleration is the variation of the velocity in a unit of time.
Therefore, from equation 1 is gotten.
[tex]W = (50kg)(0)[/tex]
Remember that g is the acceleration that a body experience as a consequence of the gravitational field.
[tex]W = 0[/tex]
