Respuesta :
Answer:
Number of turns in secondary is 20
Current in primary is 0.96 A
Explanation:
We have given number of turns in primary [tex]N_p=250[/tex]
Voltage across primary of transformer [tex]V_p=120volt[/tex]
Current in secondary coil [tex]i_s=12A[/tex]
Voltage across secondary [tex]V_s=9.6volt[/tex]
For transformer we know that [tex]\frac{N_p}{N_s}=\frac{V_p}{V_s}[/tex]
So [tex]\frac{250}{N_s}=\frac{120}{9.6}[/tex]
[tex]N_p=20[/tex]
So number of turns in primary is 20
Now [tex]\frac{N_p}{N_s}=\frac{i_s}{i_p}[/tex]
[tex]\frac{250}{20}=\frac{12}{i_p}[/tex]
[tex]i_p=0.96A[/tex]
Current in primary of transformer is 0.96 A
The current in the primary coil is 0.96A, and the number of turns in the secondary coil is 20.
Transformer:
Given that the number of turns in the primary coil is, N = 250
Let the number of turns in the secondary coil be N'.
Also, the voltage of the primary is, V = 120V
whereas the voltage of the secondary is, V' = 9.6V
From the transformer equation we can write :
[tex]\frac{N}{N'} =\frac{V}{V'} \\\\N' =\frac{V'}{V}\times N \\\\N'=\frac{9.6}{120}\times250[/tex]
N' = 20 turns
Now, the current in the secondary coil is given to be, I' = 12A
Let the current in the primary coil be, I
the number of turns and the current are inversely proportional in the case of the transformer:
[tex]\frac{N}{N'} =\frac{I'}{I} \\\\I =\frac{N'}{N}\times I' \\\\I=\frac{20}{250}\times12[/tex]
I = 0.96 A
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