Respuesta :
Answer:
The temperature in degress Celsius is 52.25°C
Explanation:
According the equation:
[tex]V(\rho _{a} -\rho _{t})g=mg\\\rho _{a} -\rho _{t}=\frac{n}{V} =\frac{340}{2950} =0.115kg/m^{3}[/tex]
[tex]\rho _{t}=\rho _{a} -0.115=1.2-0.115=1.085kg/m^{3}[/tex]
The temperature is:
[tex]T=\frac{P}{\rho _{t} R} =\frac{1.013x10^{5} }{1.085*287.05} =325.25K=52.25[/tex]°C
The temperature in degrees Celsius is 52.25°C
Important information:
The molar mass of air is 28.97 g/mol and its density is 1.20 kg/m3.
Calculation of the temperature:
We know that the density should be calculated by applying the below computation
[tex]= 340 \div 2950\\\\= 0.115 kg/mg^3[/tex]
Now the temperature of the hot air inside the balloon is
[tex]= \frac{1.03\times 10^{5}}{1.085 \times 287.05} \\\\= 325.25k[/tex]
= 52.25°C
hence, we can conclude that the temperature in degrees Celsius is 52.25°C
Find out more information about the Temperature here:https://brainly.com/question/7510619?referrer=searchResults
