Answer:
The magnitude of induced emf is 0.122 V
Explanation:
Given:
Number of turns [tex]N = 30[/tex]
Magnetic field [tex]B = 0.30[/tex] T
Radius of coil [tex]r = \frac{d}{2} = 5.5 \times 10^{-2}[/tex] m
Change in time [tex]dt = 0.70[/tex] sec
For finding the magnitude of induced emf,
According to the faraday's law,
[tex]\epsilon = -N \frac{d\phi}{dt}[/tex]
Where [tex]\phi =[/tex] magnetic flux
[tex]\phi = BA[/tex]
Where [tex]A = \pi r^{2}[/tex] area of coil
For finding magnitude we neglect minus sign,
[tex]\epsilon = N \frac{B\pi r^{2} }{dt}[/tex]
[tex]\epsilon = \frac{30 \times 0.30 \times 3.14 \times (5.5 \times 10^{-2} )^{2} }{0.70}[/tex]
[tex]\epsilon = 0.122[/tex] V
Therefore, the magnitude of induced emf is 0.122 V
