Answer:
Time period = 2.5 sec
Frequency = 0.4 Hz
Amplitude = 0.26 m
Maximum speed = 0.65 [tex]\frac{m}{s}[/tex]
Explanation:
No. of oscillations = 14
Time = 35 sec
(a). Time period of oscillation
[tex]T = \frac{35}{14}[/tex]
T = 2.5 sec
This is the time period.
(b). Frequency
[tex]f = \frac{1}{T}[/tex]
[tex]f = \frac{1}{2.5}[/tex]
f = 0.4 Hz
This is the frequency.
(c). Oscillation from one side to another side is 65 - 13 = 52 cm = 0.52 m
Hence amplitude
[tex]A = \frac{1}{2} (0.52)[/tex]
A = 0.26 m
This is the amplitude.
(d). The maximum speed
[tex]v_{max} = (2 \pi f) A[/tex]
[tex]v_{max} =[/tex] 2 × 3.14 × 0.4 × 0.26
[tex]v_{max} =[/tex] 0.65 [tex]\frac{m}{s}[/tex]