Answer:
Maximum theoretical power (output) = 9.80 W
Explanation:
The efficiency of power is given by:
η = [tex]1 - \frac{T_H}{T_H}[/tex] = [tex]\frac{T_H - T_C}{T_H}[/tex]
Where [tex]T_H[/tex] is temperature of hot reservoir and [tex]T_C[/tex] is temperature of cold reservoir.
given:
[tex]T_H[/tex] = 500 K
[tex]T_C[/tex] = 310 K
The efficiency of power cycle
η = [tex]\frac{500 K - 310 K}{500 K}[/tex]
η = [tex]\frac{190 K}{500 K}[/tex]
η = 0.38
Efficiency in terms of heat rejected and heat transferred to power cycle is as follows
η = [tex]1 - \frac{Q_{rejected}}{Q_{transferred}}[/tex]
known that: η = 0.38 and [tex]Q_{rejected}[/tex] = 16 MW
0.38 = [tex]1 - \frac{16 MW}{Q_{transferred}}[/tex]
[tex]\frac{16 MW}{Q_{transferred}}[/tex] = 1 - 0.38
[tex]\frac{16 MW}{Q_{transferred}}[/tex] = 0.62
[tex]Q_{transferred}[/tex] = 25.80 MW
W = [tex]Q_{transferred}[/tex] - [tex]Q_{rejected}[/tex]
W = 25.80 MW - 16 MW
W = 9.80 MW
