Answer:
The intensity of this wave is 10.87 W/m²
The energy flowing through the given area is 6.10J
Explanation:
The expression for the intensity of the electromagnetic wave is,
[tex]I =\frac{1}{2} c\varepsilon _0E^2_m[/tex]
Here, [tex]{\varepsilon _0}[/tex] is the permittivity of the free space,
[tex]E _m[/tex] is the electric field amplitude
c is the speed of the light.
Substitute [tex]3 \times {10^8}{\rm{ m/s}}[/tex] for c, [tex]8.85\times 10^-^1^2[/tex] N.m² for [tex]{\varepsilon_0}[/tex], and 81.1 V/m for [tex]{E_{\rm{m}[/tex]
[tex]I = \frac{1}{2} (3\times 10^8)(8.85\times 10^-^1^2)(90.5)^2\\\\I=\frac{21.745}{2} \\\\I=10.87W/m^2[/tex]
Therefore, the intensity of this wave is 10.87 W/m²
The expression for the energy is,
[tex]E =IAt[/tex]
Here, I is the intensity of the electromagnetic wave, A is the area, and t is the time.
Substitute 10.87W/m² for I, 0.0291 m² for A, and 19.3 s for t.
E = (10.87)(0.0291)(19.3)
E = 6.10J
Hence, The energy flowing through the given area is 6.10J
