Answer:
98% Confidence interval: (26.939,42.461)
Step-by-step explanation:
We are given the following in the question:
Sample mean, [tex]\bar{x}[/tex] = 34.7 bushels per acre
Sample size, n = 9
Alpha, α = 0.05
Sample standard deviation, s = 8.04 bushels per acre
Degree of freedom = n - 1 = 8
98% Confidence interval:
[tex]\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}[/tex]
Putting the values, we get,
[tex]34.7 \pm 2.896(\dfrac{8.04}{\sqrt{9}} )\\\\ = 34.7 \pm 7.761 = (26.939,42.461)[/tex]
is the required confidence interval for the true mean yield.
