Answer:
The magnitude of induced emf is 5.4 V
Explanation:
Given:
Magnetic field [tex]B = 0.9[/tex] T
Area of loop [tex]\Delta A = 3[/tex] [tex]m^{2}[/tex]
Time take to reduce loop to zero [tex]\Delta t = 0.5[/tex] sec
To find induced emf we use faraday's law,
Induced emf is given by,
[tex]\epsilon = -\frac{\Delta \phi}{\Delta t}[/tex]
Here minus sign shows lenz law, for finding magnitude of emf we ignore it.
Where [tex]\phi = B\Delta A[/tex]
Put the value of flux and find induced emf,
[tex]\epsilon = \frac{B\Delta A}{\Delta t}[/tex]
[tex]\epsilon = \frac{0.9 \times 3}{0.5}[/tex]
[tex]\epsilon = 5.4[/tex] V
Therefore, the magnitude of induced emf is 5.4 V
