A NaOH(aq) solution with a pH value of 13 is used to determine the molarity of a HCl(aq) solution. A 10.0-mL sample of the HCl(aq) is exactly neutralized by 16.0 mL of 0.100 M NaOH(aq). During this laboratory activity, appropriate safety equipment was used and safety procedures were followed. Determine the pH value of a solution that has a H+(aq) ion concentration 10 times greater than the original NaOH(aq) solution.

Respuesta :

Answer:

pH of the H⁺(aq) is 0

Explanation:

It is possible to know the  concentration of a HCl(aq) solution by titration with a solution of NaOH(aq) with known concentration. The reaction is:

HCl(aq) +  NaOH(aq) → H₂O(l) + NaCl(aq)

The added moles of NaOH are equal to moles of HCl and as you know volume of HCl added you will obtain concentration of HCl.

Now, a solution of H⁺(aq) with a concentration 10 times greater than original NaOH(aq) solution -0.100M-, has a concentration of 1.00M H⁺(aq), the pH of this solution is:

pH = -log (1.00M H⁺(aq) = 0

That means pH of the H⁺(aq) is 0

The pH of the solution that has a H+ ion concentration 10 times greater than the original NaOH solution is 12.

What is pH of a solution?

The pH of a solution is the negative logarithm to base ten of the hydrogen ions concentration of the solution.

  • pH = - log[H-]

The pH of the NaOH solution is 13

The [H+] = 10^-13

A solution that has a ten times hydrogen ion of the original NaOH solution = 10 × 10^-13 = 10^-12

pH = - log(10^12)

pH = 12

Therefore, the pH of the solution is 12.

Learn more about pH at: https://brainly.com/question/15309966