Suppose two chemical reactions are linked together in a way that the O2 produced in the first reaction goes on to react completely with Mg to form MgO in the second reaction. Reaction one: 2 KClO3 → 3 O2 + 2 KCl Reaction two: 2 Mg + O2 → 2 MgO If you start with 4 moles of KClO3, how many moles of MgO could eventually form

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ruchi86 ruchi86 · Answer 1 · 2020-04-11T04:48:40+02:00

Answer:

Numbe of mole of MgO form=12

Explanation:

First calculate the number of mole of [tex]O_2[/tex] produced from 4 mole of [tex]KCLO_3[/tex]

Balance the first reaction:

[tex]2KClO_3 \rightarrow 3 O_2 + 2 KCl[/tex]

from the above balanced reaction it is clearly that,

by unitry method,

2 mole of [tex]KCLO_3[/tex] produced 3 mole of [tex]O_2[/tex]

1 mole of [tex]KCLO_3[/tex] produced 1.5 mole of [tex]O_2[/tex]

from 4 mole of [tex]KCLO_3[/tex] [tex]4\times 1.5[/tex] mole of [tex]O_2[/tex] produced

hence we have 6 mole of [tex]O_2[/tex] and this total oxygen will react with Mg

Balance the second reaction:

[tex]2Mg + O_2 \rightarrow 2 MgO[/tex]

since produced oxygen in first reaction is reacted completely with Mg means Mg is given in excess quantity,

From the second balanced reacion it is clearly that,

1 mole of [tex]O_2[/tex] produced 2 Mole of MgO

hence 6 mole of [tex]O_2[/tex] will produce 12 mole of MgO

Numbe of mole of MgO form=12