Answer:
The maximum traverse acceleration is [tex]\alpha = 31346.095 m/s^2[/tex]
Explanation:
Generally the maximum transverse acceleration is mathematically represented as
[tex]\alpha = w^2 A[/tex]
Where [tex]w[/tex] is the angular velocity which is mathematically evaluated as
[tex]w = 2 \pi f[/tex]
Substituting the values given in the question
[tex]w = 2 * 3.142 * 630[/tex]
[tex]= 3958.92 rad/s[/tex]
A is the A is amplitude with a value of 2.0mm [tex]= \frac{2}{1000} = 0.002m[/tex]
Substituting this into the formula for maximum transverse acceleration
[tex]\alpha = 3958.96^2 * 0.002[/tex]
[tex]= 31346.095 m/s^2[/tex]
