Answer:
The wavelength is [tex]\lambda = 4.28*10^{-4}mm[/tex]
Explanation:
Generally wavelength is mathematically represented as
[tex]\lambda = \frac{D}{L} * \Delta y[/tex]
Where [tex]\Delta y[/tex] is the difference between the minimums and its value is = 5.9mm
D is the slit spacing with a value = 0.18 mm
L is the distance between the slit and the screen with
value = 6.2cm = [tex]= 6.2 *10=620mm[/tex]
The distance first and the fifth minimum is usually = 4[tex]\lambda[/tex]
So the equation above becomes
[tex]D * \frac{\Delta y}{L} = 4 \lambda[/tex]
Making wavelength the subject
[tex]\lambda = \frac{D * \frac{\Delta y}{L} }{4}[/tex]
Substituting value
[tex]\lambda = \frac{0.18 * \frac{5.9}{620} }{4}[/tex]
[tex]\lambda = 4.28*10^{-4}mm[/tex]
