A chemist is trying to determine the molar mass of a certain protein. 1.00 x 10 -3 g of it was dissolved in enough water to make 1.00 mL of solution. The osmotic pressure of this solution was found to be 1.12 torr at 25.0°C. Calculate the molar mass of the protein.

Respuesta :

Answer:

Molar mass of protein is [tex]1.66\times 10^{4}[/tex] g/mol

Explanation:

Protein is a non-electrolyte. For a non-electrolyte-

                                 We know, [tex]\pi =c.R.T[/tex]

where [tex]\pi[/tex] represents osmotic pressure of solution, c represents molarity of solution and T represents temperature in kelvin scale.

Let's assume molar mass of protein is M g/mol

Then [tex]c=\frac{\frac{1.00\times 10^{-3}}{M}}{1.00}\times 1000mol/L=\frac{1.00}{M}mol/L[/tex]

R = 0.0821 L.atm/(mol.K)

[tex]\pi[/tex] = 1.12 torr = 0.00147 atm

T = (273+25) K = 298 K

So, [tex]0.00147=\frac{1.00}{M}\times 0.0821\times 298[/tex]

or, M = [tex]1.66\times 10^{4}[/tex]

So, molar mass of protein is [tex]1.66\times 10^{4}[/tex] g/mol