g The exchange rate from US Dollars (USD) to Indian Rupee (INR) is normally distributed with an average of 67.43 and a standard deviation of 1.2. What is the exchange rate for the 20th percentile? Enter your answer to 4 decimal places.

Respuesta :

Answer:

The exchange rate for the 20th percentile is 66.422

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 67.43 \sigma = 1.2[/tex]

What is the exchange rate for the 20th percentile?

This is X when Z has a pvalue of 0.2. So it is X when Z = -0.84.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.84 = \frac{X - 67.43}{1.2}[/tex]

[tex]X - 67.43 = -0.84*1.2[/tex]

[tex]X = 66.422[/tex]

The exchange rate for the 20th percentile is 66.422