Answer:
Explanation:
Given that,
Mass m = 2kg
Initial Velocity Vi = 3m/s
Force applied. = 4N
Distance cause by the force applied d = 5m
a. Work done by the force applied?
Work done by force applied can be determined by
W = F×d•Cosx
Where x is direction is the force and displacement
The force and displacement are in the same direction, then, x =0°
W = F×d•Cosx
W = 4×5Cos0
W = 20J.
b. Final velocity
The change in kinetic energy is equal to work done
∆K.E = W
½mVf² - ½mVi² = W
½mVf² = ½mVi² + W
½ × 2 Vf² = ½ × 2 × 3² + 20
Vf² = 9+20
Vf² = 29
Vf = √29
Vf = 5.39m/s
The final velocity is 5.39m/s
The velocity of the object after the force was applied is equal to 5.39 m/s.
Given the following data:
a. To find the work done by this force:
Mathematically, the work done by an object is given by the formula;
[tex]Work\;done = force \times displacement[/tex]
Substituting the values into the formula, we have;
[tex]Work\;done = 4 \times 4[/tex]
Work done = 20 Joules
b. To determine the velocity of the object after the force was applied, we would apply the law of conservation of energy:
Kinetic energy after - Kinetic energy before = Work done.
[tex]\frac{1}{2} MV_f^2 - \frac{1}{2} MV_i^2 = Work\;done\\\\\frac{1}{2} \times 2 \times V_f^2 - \frac{1}{2} \times 2 \times 3^2 = 20\\\\V_f^2 -9 = 20\\\\V_f^2 = 20 + 9\\\\V_f^2 = 29\\\\V_f = \sqrt{29} \\\\V_f = 5.39 \;m/s[/tex]
Read more: https://brainly.com/question/22599382
