The front of a garage needs to be painted. The total area except for the door will be painted. The door is 1.5 m high and 2 m wide. What are the answers for A, B, and C?
Please help!

The front of a garage needs to be painted The total area except for the door will be painted The door is 15 m high and 2 m wide What are the answers for A B and class=

Respuesta :

Answer:

The answer for A is [tex]7.85m^{2}[/tex].

The answer for B is 4 cans.

The answer of C is $98.

Step-by-step explanation:

A-

Multiply 2.5 by 3.5 and you'll get 8.75 Multiply 3.5 by 1.2 and you'll get 4.2; divide and your answer will be 2.1  Add to 8.75 Get 10.85 Subtract from area of door ( 3m because 1.5 times 2 is 3) and you'll get 7.85

B-

Divide 7.85 by 2.5 and you'll get 3.104; round that and you'll get 4 cans.

C-

Multiply the amount of cans (4) by 24.5. Do this and you'll get $98.

                                   Hope this was helpful!!!

A. 8.45 m² paint will be required to paint the front of the garage except the area of the rectangle door.

B. 4 cans of paint required to paint the front of the garage.

C. The cost to paint the front of the garage is $98.

What is the area of a rectangle?

The area of a rectangle is the total area covered by that rectangle.

The area of a rectangle = length × width.

We need to find the area of the front of the garage except the door.

The area of the door = width × height = 2 × 1.5 m² = 3 m².

Therefore, the area to be painted

= front area of the garage - the area of the door

= [(3.5 × 2.5) + ([tex]\frac{1}{2}[/tex] × 3.5 ×1.2) - 3] m²

= [8.75 + 2.1 - 3] m²

= 7.85 m²

If a can has 2.5 m² paint, then the total number of cans required

= [tex]\frac{7.85}{2.5}[/tex]

= 3.14

≈ 4.

A can costs $24.50, then the total cost to paint the front of the garage

= 4 × $ 24.5

= $ 98

Learn more about area of a rectangle here: https://brainly.com/question/15218510

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