Answer:
We want to estimate the population proportion of people who passed out at G forces greater than [tex]p[/tex] and for this case the best estimator is given by:
[tex]\hat p =\frac{X}{n}[/tex]
And replacing we got:
[tex]\hat p =\frac{576}{1373}= 0.420[/tex]
So then the proportion of people who pass out at more than 6Gs is 0.420 or 42.0%
Step-by-step explanation:
For this case we have the following info given:
X= 576 represent the number of people who passed out at G forces greater than 6
n= 1373 represent the sample size for this case
We want to estimate the population proportion of people who passed out at G forces greater than [tex]p[/tex] and for this case the best estimator is given by:
[tex]\hat p =\frac{X}{n}[/tex]
And replacing we got:
[tex]\hat p =\frac{576}{1373}= 0.420[/tex]
So then the proportion of people who pass out at more than 6Gs is 0.420 or 42.0%