An object on the flat bed of a truck that is accelerating along a straight, horizontal road. The coefficient of staticfriction is 0.300 in this case. Of the following choices, which is the lowest value of acceleration that would resultin the object sliding on the bed of the truck

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Answer:

The lowest value of acceleration that result in the object sliding on the bed of the truck is 2.94 m/s²

Explanation:

The frictional force is equal to:

[tex]f=ma\\\mu mg=ma\\ a=\mu g[/tex]

Where

μ = coefficient of static friction = 0.3

g = gravity = 9.8 m/s²

Replacing:

[tex]a=0.3*9.8=2.94m/s^{2}[/tex]

The lowest value of acceleration that result in the object sliding on the bed of the truck is 2.94 m/s²

Calculation of the lowest value of acceleration:

Since f = ma

Here

f means the force

m means the mass

And, a means the acceleration

Also,

a = μg

That means

μ = coefficient of static friction = 0.3

g = gravity = 9.8 m/s²

So, here the acceleration should be

= 0.3 * 9.8

= 2.94

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