Answer:
1) Vout = -25 V
2) Vout = -25.61 V
The sensitivity is 0.122 V/Ω
Explanation:
The equation for Vout is:
[tex]V_{out} =-\frac{R_{f} }{R_{i} } (\frac{V_{in}R_{s} }{R_{str} } )[/tex]
1) Given:
Rf = 10 K
Ri = 1 K
Rs = 100 Ω
Rstr = 200 Ω
Vin = 5 V
[tex]V_{out} =-\frac{10}{1} (\frac{5*100}{200} )=-25V[/tex]
2) Now, Rs = 105 Ω
[tex]V_{out} =-\frac{10}{1} (\frac{5*105}{205} )=-25.61V[/tex]
The sensitivity is equal to:
[tex]S=\frac{V_{out2}-V_{out1}}{R_{s2}-R_{s1} } =\frac{25.61-25}{105-100} =0.122V/ohm[/tex]
