Respuesta :
Answer: The concentartion of solution will be 0.224 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute =[tex]\frac{\text{Given mass}}{\text{Molar mass}}=\frac{10.0g}{162.2g/mol}=0.0616moles[/tex]
[tex]{V_s}[/tex] = volume of solution in ml = 275 ml
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{0.0616\times 1000}{275ml}=0.224mole/L[/tex]
Therefore, the concentration of solution will be 0.224 M
The concentration of FeCl₃ in the solution is 0.224M. The correct option is the first option - 0.224 M
First, we will determine the number of moles of FeCl₃ present in the solution
Mass of FeCl₃ = 10.0 g
Using the formula
[tex]Number\ of\ moles =\frac{Mass }{Molar\ mass}[/tex]
Molar mass FeCl₃ = 162.204 g/mol
∴ Number of moles of FeCl₃ present = [tex]\frac{10.0}{162.204}[/tex]
Number of moles of FeCl₃ present = 0.06165 mole
Now,
For the concentration of FeCl₃ in the solution
From the formula
[tex]Concentration = \frac{Number\ of\ moles }{Volume}[/tex]
Volume of the solution = 275 mL = 0.275 L
∴ Concentration of FeCl₃ in the solution = [tex]\frac{0.06165}{0.275}[/tex]
Concentration of FeCl₃ in the solution = 0.224 M
Hence, the concentration of FeCl₃ in the solution is 0.224M. The correct option is the first option - 0.224 M
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