Answer:
a) The magnitude of the emf induced is 0.0055 V
b) The rate should the are be changed is 0.0037 m²/s
Explanation:
a) The magnitude of the emf induced in the loop is equal to:
[tex]E=A\frac{dB}{dt} =0.025*0.22=0.0055V[/tex]
b) The induced emf is equal to:
[tex]V=B\frac{dA}{dt} +A\frac{dB}{dt} \\0=1.5\frac{dA}{dt} +0.0055\\\frac{dA}{dt} =-0.0037m^{2} /s[/tex]