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In ΔVWX, the measure of ∠X=90°, WV = 17, VX = 15, and XW = 8. What ratio represents the sine of ∠W?

Respuesta :

opudodennis

Answer:

[tex]Sin \ \angle W=\frac{15}{17}[/tex]

Step-by-step explanation:

-In a right triangle, the Sine of the base acute angle is usually given as:

[tex]Sin \angle (base)=\frac{Opposite \ Length}{Hypotenuse}[/tex]

-In  ΔVWX,, VX is the opposite and WV the hypotenuse.

-Therefore, sine of ∠Wis calculated as;

[tex]Sin \ \angle W=\frac{Opp}{Hyp}\\\\=\frac{15}{17}[/tex]

Hence, sine of  ∠W is given represented by the ratio [tex]\frac{15}{17}[/tex]

re79112

Answer:

15/17

Step-by-step explanation:

using the rule of SOH CAH TOA