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Answer:
Answer is 120
Step-by-step explanation:
[tex]here \: all \: the \: terms \: goes \: in \: the \: multiple \: \\ of \: 2 \\ therefore \: {n}^{th} \: term \: is \: 2n \\ when \: n = 1 \: we \: get \: 2 \times 1 = 2 \\ to \: find \: {60}^{th} \: term \: on \: substituting \: n = 60 \: in \: 2n \\ 2 \times 60 = 120 \\ hence \: {60}^{ th} \: term \: is \: 120[/tex]
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The 60th term of the sequence is 120.
How do we find the nth term of an Arithmetic Sequence?
The nth term of an arithmetic sequence can be found by using the following formula.
[tex]a_{n} =a+(n-1)d[/tex]
- a_n is the nth term.
- a is the first term.
- d is the common difference of the AP.
We know the values of a and d from the given sequence.
a = 2
d = 4 - 2 = 2
∴ a_60 = 2 + (60-1)*2
= 2 + 59*2
= 2 + 118
= 120
Therefore, we have found the value of the 60th term of the sequence as 120.
Learn more about arithmetic sequences here: https://brainly.com/question/6561461
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