The probability of getting a 3 and an even number = [tex]\frac{1}{12}[/tex]
Step-by-step explanation:
Given,
Two fair dice are rolled.
To find the probability of getting a 3 and an even number.
Formula
The probability of an event = the possible outcomes ÷ total number of outcomes.
Now,
The total outcomes are =
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(3,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6) = 36
Required outcomes = (3, an even number) = (3,2),(3,4),(3,6) = 3
Hence,
The probability of getting a 3 and an even number = [tex]\frac{3}{36} = \frac{1}{12}[/tex]
