Given:
The sum of 5 consecutive integers is 110.
Let the sequence be x, x + 1, x + 2, x + 3, x + 4
We need to determine the fourth number in the sequence.
Value of x:
Since, the sum of 5 consecutive integers is 110.
Thus, we have;
[tex]x+x+1+x+2+x+3+x+4=110[/tex]
Adding the like terms, we have;
[tex]5x+10=110[/tex]
[tex]5x=100[/tex]
[tex]x=20[/tex]
Thus, the value of x is 20.
Fourth term:
The fourth term of the sequence is x + 3
Substituting x = 20 in the term, we get;
Fourth term = 20 + 3 = 23
Thus, the fourth term of the sequence is 23.
