What is the ratio of resistivity of 2 resistors with identical resistances and area of cross section,
where the first resistor is twice the length of the second resistor?

Respuesta :

Explanation on the photo
Ver imagen maxl14

This question involves the concepts of the resistance, resistivity, and length.

The ratio of the resistivity of the two resistors is "0.5".

RESISTIVITY

Resistance of a wire can be given in terms of resistivity through following formula:

[tex]R=\frac{\rho L}{A}[/tex]

where,

  • R = resistance
  • [tex]\rho[/tex] = resistivity
  • L = length
  • A = area of cross-section

Using subscript 1 for first resistor:

[tex]R_1=\frac{\rho_1 L_1}{A_1}[/tex]

Using subscript 2 for first resistor:

[tex]R_2=\frac{\rho_2 L_2}{A_2}[/tex]

Dividing both equations:

[tex]\frac{R_1}{R_2}=\frac{\frac{\rho_1 L_1}{A_1}}{\frac{\rho_2 L_2}{A_2}}[/tex]

It is given that:

  • R₁ = R₂
  • A₁ = A₂
  • L₁ = 2L₂

Therefore,

[tex]1=\frac{\rho_1(2L_2)}{\rho_2(L_2)}[/tex]

[tex]\frac{rho_1}{\rho_2}=0.5[/tex]

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