The distance traveled by Randy is 500 m
The Four coordinates of the rectangle are given by the following points
Let the points be A, B, C and D
A (-5,-2)
B ( -5,9)
C ( 9,9 )
D ( 9,-2)
Each unit on the grid represents 10 meters
The Distance formula for two points
[tex](x_1, y_1) \; and\; (x_2, y_2) \; is \; given\; by \; formula \\\\d = \sqrt{(x_1-x_2)^2- (y_1-y_2)^2 } ........(1)[/tex]
On Putting he values of A and B in equation (1) we get
[tex]d_{AB} = 11[/tex]
Similarly on putting the values of B and C in equation (1) we get
[tex]d_{BC} = 14[/tex]
now the perimeter of rectangle is given by equation (2)
[tex]\rm Perimeter \; of\; Rectangle = 2( d_{AB} + d_{BC}).......(2)[/tex]
Perimeter = 2[tex]\times[/tex](11 + 14) = 50
Since each unit on the grid represents 10 meters hence
The distance traveled by Randy = 10 [tex]\times[/tex] 50 = 500 m
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