Answer:
55 C
Explanation:
When a certain substance is heated, the temperature of the substance increases according to the equation
[tex]Q=mC\Delta T[/tex]
where
Q is the heat supplied to the substance
m is the mass of the substance
C is the specific heat of the substance
[tex]\Delta T[/tex] is the change in temperature of the substance
The equation can be rewritten as
[tex]\Delta T=\frac{Q}{mC}[/tex]
In this problem, the two pots both contain water, so the specific heat (C) is the same. Also, the same amount of heat is supplied, so Q is the same.
However, pot A contains 1 liter of water, while pot B containes 3 liters: this means that the mass of water in pot B is 3 times the mass of water in pot A,
[tex]m_B = 3 m_A[/tex]
Since [tex]\Delta T[/tex] is inversely proportional to the mass, this means that
[tex]\Delta T_A=3\Delta T_B[/tex]
The change in temperature of the water in pot B is
[tex]\Delta T_B=35C-25C=10C[/tex]
So, the change in temperature of the water in pot A is
[tex]\Delta T_A=3\Delta T_B=3(10)=30C[/tex]
So, the final temperature of pot A is
[tex]T_A =T_0+\Delta T_A=25C+30C=55C[/tex]
