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In baseball, a player's batting average is the proportion of times that the player gets a hit out of

his total number of times at bat. Suppose we select a Major League Baseball player at random.

The random variable X= the player's batting average can be modeled by a normal distribution

with mean y = 0.261 and standard deviation o = 0.034. Use the 68–95-99.7 rule to approximate:

(a) The probability that a randomly selected player has a batting average greater than 0.329

Respuesta :

The probability that a randomly selected player has a batting average greater than 0.329 is; 2.275%

Random Distribution

We are given;

  • Mean; x' = 0.261
  • Standard deviation; σ = 0.034

We want to find the probability that a randomly selected player has a batting average greater than 0.329

P(x > 0.329);

Z = (X' - μ)/σ

Z = (0.261 - 0.329)/0.034

Z = -2

From online p-value from z-score calculator, we have;

p-value = 2.275%

Read more about random distribution at; https://brainly.com/question/18383093

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