Answer: 0.85075J/g.K
Explanation:
Mass of the material = 100g
Energy (Q) = 5104.5J
T1 = 20°C = 293K
T2 = 80°C = 353K
Formula for heat energy (Q) = mc ∇T
Q = mc∇T
∇T = T2 - T1
∇T = 353K - 293K = 60K
Q = mc∇T
C = Q / m∇T
C = (5104.5) / (100 * 60)
C = 0.85075 J/gK
The specific heat capacity of the material is 0.85075J/gK.
Answer:
The specific heat of the material is 0.851 J/g°C
Explanation:
Step 1: Data given
Mass of the sample = 100 grams
Amount of heat required = 5104.5 Joules
Initial temperature = 20.0°C
Final temperature = 80.0 °C
Step 2: Calculate the specific heat of the material
Q = m* c¨* ΔT
⇒with Q = the amount of energy = 5104.5 J
⇒with m = the mass of the material = 100 grams
⇒with c = the specific heat of the material = TO BE DETERMINED
⇒with ΔT = the change of temperature = T2 - T1 = 80.0 °C - 20.0 °C = 60.0 °C
5104.5 = 100 * c * 60
c = 5104.5 / (100*60)
c = 0.851 J/g°C
The specific heat of the material is 0.851 J/g°C
