Respuesta :
Answer:
capacitance of the capacitor = 0.18 μ F
Explanation:
Area of the plate A = 0.063 m x 5.4 m = 0.3402 m²
distance between the plate d = 3.5 × 10–5 m
dielectric value for Teflon K = 2.1
capacitance of capacitor = ?
Formula for capacitance of parallel plate is as follows ,
[tex]C= \frac{K\epsilon_0 A}{d}[/tex] (Where [tex]\epsilon_0 = 8.82 \times 10^-12\ \frac{F}{m}[/tex] )
putting the values in the equation,
C = [tex]\frac{2.1\times8.82\times10^-12\times0.3402 }{3.5\times10^-5}[/tex] [tex]=0.18\times 10^-6[/tex] =0.18 μ F
