The centre of the circle will be at (4, -3) and the radius is 4.
What is the equation of a circle?
We are aware that a circle's general equation is [tex](x-h)^{2} + (y-k)^{2} = r^{2} ,[/tex]where (h, k) is its center and r is its radius. Therefore, to bring the constant term to the righthand side of the equation.
Given
[tex](x-4)^{2} + (y+3)^{2} = 16[/tex]
-h = -4
h = 4
-k = 3
k = -3
Centre = (h, k) = (4, -3)
[tex]r^{2} = 16\\r = \sqrt{16} = 4[/tex]
Therefore, The centre of the circle will be at (4, -3) and the radius is 4.
to learn more about the equation of the line refer to :
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