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On a coordinate plane, triangle A B C is shown. Point A is at (negative 2, negative 4), point B is at (2, negative 1), and point C is at (3, negative 4).
Triangle ABC is an isosceles triangle in which side
AB = AC. What is the perimeter of triangle ABC?

5 + StartRoot 10 EndRoot units
10 + StartRoot 10 EndRoot units
10 StartRoot 10 EndRoot units
50 units

On a coordinate plane triangle A B C is shown Point A is at negative 2 negative 4 point B is at 2 negative 1 and point C is at 3 negative 4 Triangle ABC is an i class=

Respuesta :

tdelaney051603

Answer:

The answer is B.

akposevictor

The perimter of the isosceles triangle ABC in the image given is: 10 + √10 units.

What is the Perimeter of a Triangle?

Perimeter of a triangle = sum of all three sides of the triangle.

The perimeter of the isosceles triangle in the given coordinate plane = 2(AC) + BC

AC = 5 units

Use the distance formula, [tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex], to find BC:

B (2, -1)

C (3, -4)

BC = √[(3−2)² + (−4−(−1))²]

BC = √10

Perimeter = 2(5) + √10 = 10 + √10 units

Learn more about perimeter of triangle on:

https://brainly.com/question/24382052

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