Answer:
Its actually 27.9 grams for anyone working on CK12
Explanation:
The mass of iron needed to react with 16.0 grams of sulphur is 28 grams
Let's write the full chemical equation of the reaction. Therefore,
S₈ + 8Fe → 8FeS
Therefore,
molar mass of 8 moles of iron = 56 × 8 = 448 grams
molar mass of S₈ = 32 × 8 = 256 grams
Therefore,
256g of Sulphur needs 448 g of Iron
16 g of sulphur will ?
cross multiply
mass of Iron needed = 16 × 448 / 256
mass of Iron needed = 7168 / 256
mass of Iron needed = 28 grams
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