Respuesta :
Answer:
4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium
Explanation:
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:
- HCl: 2 moles
- Na: 1 mole
- NaCl: 2 moles
- H₂: 1 mole
You know the following masses of each element:
- H: 1 g/mole
- Cl: 35.45 g/mole
- Na: 23 g/mole
So, the molar mass of each compound participating in the reaction is:
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
- Na: 23 g/mole
- NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
- H₂: 2* 1 g/mole= 2 g/mole
Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- Na: 1 mole* 23 g/mole= 23 g
- NaCl: 2 moles* 58.45 g/mole= 116.9 g
- H₂: 1 mole* 2 g/mole= 2 g
So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?
[tex]mass of H_{2} =\frac{175 g of HCl*2g ofH_{2} }{72.9 g of HCl}[/tex]
mass of H₂= 4.8 g
4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium
Answer:
4.85 grams of H2 will be produced
Explanation:
Step 1: Data given
Mass of HCl = 175 grams
Molar mass of HCl = 36.46 g/mol
Molar mass H2 = 2.02 g/mol
Step 2: The balanced equation
2HCI + Na —> 2NaCl +H2
Step 3: Calculate moles HCl
Moles HCl = mass HCl / molar mass HCl
Moles HCl = 175 grams / 36.46 g/mol
Moles HCl = 4.80 moles
Step 4: Calculate moles H2
For 2 moles HCl we need 1 mol Na to produce 2 moles NaCl and 1 mol H2
For 4.80 moles HCl we'll have 4.80/ 2 = 2.40 moles H2
Step 5: Calculate mass H2
Mass H2 = moles H2 * molar mass H2
Mass H2 = 2.40 moles * 2.02 g/mol
Mass H2 = 4.85 grams
4.85 grams of H2 will be produced
