In a sample of 115 115 curtains, the average length was found to be 32.2in. 32.2 ⁢ in. With a standard deviation of 0.8 0.8 . Give a point estimate for the population standard deviation of the length of the curtains. Round your answer to two decimal places, if necessary.

Respuesta :

Answer:

The point estimate for the population standard deviation of the length of the curtains is 8.58in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

[tex]s = 0.8, n = 115[/tex]

The point estimate for the population standard deviation of the length of the curtains is [tex]\sigma[/tex]. So

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]\sigma = s\sqrt{n}[/tex]

[tex]\sigma = 0.8\sqrt{115}[/tex]

[tex]\sigma = 8.58[/tex]

The point estimate for the population standard deviation of the length of the curtains is 8.58in.