gsanouf
contestada

How many grams of water vapor would be contained in a 94.2 L cloud? (start with volume of a gas) ( molar mass of water is 18.02 g/mol)

A) 4.21 g
B) 6.29 g
C) 75.78 g
D) 117.00 g

Respuesta :

Answer:

C) 75.78 g

Explanation:

Given parameters:

Volume of cloud  = 94.2L

Molar mass of water  = 18.02g/mol

Unknown:

Mass of water  = ?

Solution:

Water is the bulk component of a cloud. To solve this problem, let us find the number of moles of the water using the relationship below first;

            Number of moles of water  = [tex]\frac{volume of water }{22.4\\}[/tex]

          Number of moles of water  = [tex]\frac{94.2}{22.4}[/tex]   = 4.21moles

Now to find the number of moles;

           Mass of water  = number of moles of water x molar mass

                                     = 4.21 moles x 18.02g/mole

                                     =  75.78 g