A rectangular prism and a cylinder both have a height of 8 m, and their cross-sectional areas are equal at every level parallel to their respective bases. A rectangular prism and a cylinder both have a height of 8 meters. The rectangle has base dimensions of 5 meters by x. The cylinder has a radius of 3 meters. Find the volume of the prism.

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Answer:

The answer to all of the question is

1)40x

2)72

3)5.7

Step-by-step explanation:

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Volume is the measure of three dimensional space occupied by an object. The volume of the considered rectangular prism is 72π m³

How to find the volume of a right rectangular prism?

Suppose that the right rectangular prism in consideration be having its dimensions as 'a' units, 'b' units, and 'c' units, then its volume is given as:

[tex]V = a\times b \times c \: \: \rm unit^3[/tex]

We're specified that:

  • Height h of rectangular prism(assuming right rectangular prism) and cylinder = 8 m
  • Cross sectional area perpendicular to the height(assumingly) of both are same.
  • Rectagular prism's base's dimension is 5 m by x m
  • The cylinder has base of 3 m

The cross section of a cylinder (perpendicular to its height) has same area as of its base.

Same goes for cross sectional area of the rectangular prism  (perpendicular to its height).

Now, we have:

  • Cross sectional area of cylinder = Area of base of cylinder=  [tex]\pi (3)^2 = 9\pi \: \rm m^2[/tex]
  • Cross sectional area of rectangular prism = Area of base of rectangular prism = [tex]5 \times x \: \rm m^2[/tex]

Cross sectional area of cylinder=  Cross sectional area of rectangular prism

Thus, we get:

[tex]9\pi = 5x\\\\\text{Dividing both the sides by 5}\\\\\dfrac{9\pi}{5} = x\\\\\x = \dfrac{9\pi}{5} = 1.8\pi \: \rm m[/tex]


Thus, the volume of the considered right rectangular prism is:

[tex]V = a\times b \times c = 8 \times 5 \times 1.8 \pi = 72 \pi\: \: \rm m^3[/tex]

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