Answer : The element produces from alpha decay of Gadolinium-149 is, Samarium (Sm)- 145
Explanation :
Alpha decay : In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.
The general representation of alpha decay reaction is:
[tex]_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha[/tex]
When Gadolinium-149 undergoes alpha decay then it gives Samarium (Sm)- 145 isotope as a product.
The complete alpha decay reaction Gadolinium-149 will be,
[tex]_{64}^{149}\textrm{Gd}\rightarrow _{62}^{145}\textrm{Sm}+_2^4He[/tex]
Hence, the element produces from alpha decay of Gadolinium-149 is, Samarium (Sm)- 145
The nucleus formed from the alpha decay of Gadolinium-149 is Samarium-145.
An alpha particle is actually a helium nucleus. It has a mass of four and a charge of two. When a nucleus undergoes alpha decay, its mass number decreases by four units while its atomic number decreases by two units.
The alpha decay of Gadolinium-149 is shown in the equation below;
[tex]\frac{149}{64}Gd --------> \frac{145}{62} Sm + \alpha[/tex]
The nuclear reaction equation is balanced because the total mass and charge of the species are equal on both sides of the reaction equation.
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