area of a regular octagon having an apothem of 6 meters and a side length of 5 meters is [tex]120m^2[/tex] . Correct option C) .
Step-by-step explanation:
Here we have , to find What is the area of a regular octagon having an apothem of 6 meters and a side length of 5 meters . Let's find out:
We know that area of octagon is :
⇒ [tex]Area = \frac{pa}{2}[/tex] , where p is perimeter & a is apothem !
Perimeter p = 8(side) =8(5) = 40 m
Apothegm a = 6 m
So ,
⇒ [tex]Area = \frac{40(6)}{2}[/tex]
⇒ [tex]Area = \frac{240}{2}[/tex]
⇒ [tex]Area =120m^2[/tex]
Therefore , area of a regular octagon having an apothem of 6 meters and a side length of 5 meters is [tex]120m^2[/tex] . Correct option C) .
