Answer:
A possible initial point is (1,4) and a possible terminal point is (8,5)
Step-by-step explanation:
The given vector is [tex]\vec{v}=(7,1)[/tex].
We can rewrite this vector as:
[tex]\vec{v}=\binom{7}{1}[/tex]
The x-components is 7 and the y-component is 1.
We can choose initial point (a,b) and terminal point (c,d) in the first quadrant such that [tex]c-a=7[/tex] and [tex]d-b=1[/tex]
If a=1, and b= 4, then:
[tex]c-1=7[/tex] and [tex]d-4=1[/tex]
This implies that:
[tex]c=7+1=8[/tex] and [tex]d=1+4=5[/tex]
Therefore a possible initial point is (1,4) and a possible terminal point is (8,5)
