Answer:
the requested point is (0,-1)
Step-by-step explanation:
The problem is giving you the value of the slope of a line (-2), an also a point that belongs to the line. The question is to find the y-intercept of the line (that is the point at which the line crosses the y-axis.
So we use the point-slope form of a line for a given point [tex](x_0,y_0)[/tex] which in our case is (1,-3), and slope "m" (in our case "-2":
[tex]y-y_0=m(x-x_0)\\y-(-3)=(-2)(x-1)\\y+3=-2x+2\\y=-2x-1[/tex]
by solving for "y" above, we reached the "slope-intercept" form of the line, which shows clearly the value at which the line crosses the y axis: (0,-1)
given that for x=0, y becomes -1
