Answer:
-6.27 kj
Explanation:
Given data:
Energy released = ?
Mass of steam = 15 g
Initial temperature = 100°C
Final temperature = 0°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 0°C - 100°C = -100°C
Q = 15g × 4.18 j/g.°C × -100°C
Q = -6270 j
J to KJ:
-6270 j/1000 = -6.27 kj
