Answer : The molarity of [tex]MgSO_4[/tex] in the solution is 2.99 M.
Explanation : Given,
Mass of [tex]MgSO_4[/tex] = 180 g
Volume of solution = 500.0 mL
Molar mass of [tex]MgSO_4[/tex] = 120.4 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Mass of }MgSO_4\times 1000}{\text{Molar mass of }MgSO_4\times \text{Volume of solution (in mL)}}[/tex]
Now put all the given values in this formula, we get:
[tex]\text{Molarity}=\frac{180g\times 1000}{120.4g/mole\times 500.0mL}=2.99mole/L=2.99M[/tex]
Therefore, the molarity of [tex]MgSO_4[/tex] in the solution is 2.99 M.
