Answer: 1.52 atm
Explanation:
Given that:
Volume of gas V = 10.0L
Temperature T = 35.0°C
Convert Celsius to Kelvin
(35.0°C + 273 = 308K)
Pressure P = ?
Number of moles = 0.6 moles
Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
p x 10.0L = 0.6 moles x (0.0821 atm L K-1 mol-1 x 308K)
p x 10.0L = 15.17 atm L
p = 15.17 atm L / 10.0L
p = 1.517 atm (round to the nearest hundredth as 1.52 atm)
Thus, the pressure of the gas is 1.52 atm
