Respuesta :
Light shines through two polarizes. Initially, both transmission axes are aligned and then the second polarize is rotated while the other remains fixed
Explanation:
The Law of Malus gives the value of transmitted intensity through two ideal polarizes. Also When we rotate second polarizer , the vector component perpendicular to its transmission plane is absorbed, and its amplitude is reduced to
[tex]E=Ex_{0} Cos[/tex]θ
let I be the intensity of transmitted light in the y-axis while the degrees in the x-axis be -90, 180, 270, and 360.
For 0⁰ transmitted intensity = cos²(0⁰) = 1 (1st maximum on graph)
For 90⁰ transmitted intensity = cos²(90⁰) = 0 (1st minimum on graph)
For 180⁰ transmitted intensity = cos²(180⁰) = 1 (2nd maximum on graph)
For 270⁰ transmitted intensity = cos²(270⁰) = 0 (2nd minimum on graph)
For 360⁰ transmitted intensity = cos²(360⁰) = 1 (3rd maximum on graph)
According to the Malus Law, the intensity of the transmitted light will follow the curve defined by cos²θ, where θ is the angle of rotation.
Malus Law:
According to Malus law if a light of intensity I₀ is passed through a polarizer, the intensity I of the transmitted light is given by:
I = I₀cos²θ
where θ is the angle between the axis of the polarizer and the direction of polarization of the light.
So if we graph the intensity of transmitted light on the y-axis and the angle of rotation of the polarizer on the x-axis,
such that the angle of rotation of the polarizer is θ = 0, 90, 180, 270, and 360.
At 0⁰
I = I₀cos²(0°) = I₀ (1st maximum on graph)
At 90⁰
I = I₀cos²(90°) = 0 (1st minimum on graph)
At 180⁰
I = I₀cos²(180°) = I₀ (2nd maximum on graph)
At 270⁰
I = I₀cos²(0°) = 0 (2nd minimum on graph)
At 360⁰
I = I₀cos²(360°) = I₀ (3rd maximum on graph)
Learn more about Malus Law:
https://brainly.com/question/14177847?referrer=searchResults
