What is the area of the trapezoid shown below?

[tex]Height \: of \: trapezoid \\ h = \sqrt{ {25}^{2} - {7}^{2} } \\ = \sqrt{625 - 49} \\ = \sqrt{576} \\ h = 24 \: units \\ \\ b_1 = 4 \:units \\ b_2 = 7 + 4 = 11 \:units \\ \\ Area \: of \: trapezoid \\ = \frac{1}{2} (b_1 + b_2) \times h \\ \\ = \frac{1}{2} (4 + 11) \times 24 \\ = 15 \times 12 \\ \red{ \boxed{ \bold{area \: of \: trapezoid = 180 \: {units}^{2}}}} \\[/tex]

Аноним Аноним · Answer 2 · 2020-04-08T20:24:56+02:00

we will use Pythagoras theorum to find out area of that right angled triangle .

Base = 7units

hypotenuse = 25units

perpendicular= ?

Pythagoras theorem = >

base²+perpendicular ²= hypotenuse ²

(7)²+(p)²= (25)²

49+(p)²=625

(p)²= 625-49

(p)²=576

p = 24units

area of triangle =

[tex] \frac{1}{2}h+b[/tex]

[tex] \frac{1}{2} 24+7[/tex]

area of triangle = 31units ²

length of rectangle = 24units

breadth= 4units

area of rectangle = l×b

area of rectangle = 4×24

area of rectangle = 28 units .

so total area = area of triangle + area of rectangle

= 31+28

answer = 59units²